Palisade Magazine

 

Discuss: Wireless Security - How WEP works

by Arvind Doraiswamy
Discussion is open — there are 2 reader comments. Add yours.
1. Anubhav | 06 Jun 2007 1:23 PM

After going through the example mentioned, i am a bit confused that is, while doing the calculations using KSA algorithm i cannot understand the Step-2 calculation as mentioned below, i guess whether the calculations are correct or wrong:
The calculation mentioned in the example posted for Step 2:
i=1 j=2
State array: State[0]=2 State[1]=1 State[2]=0 State[3]=3
Password: K[0]=6 K[1]=2 K[2]=5 K[3]=8
j = [2 + S[1] + K[1]] mod 4 = 5 mod 4 = 1
Swap(State[1], State[2]) = Swap(1,0)
State[0]=2 State[1]=0 State[2]=1 State[3]=3

The calculation as per me should be:
i=1 j=2
State array: State[0]=2 State[1]=1 State[2]=0 State[3]=3
Password: K[0]=6 K[1]=2 K[2]=5 K[3]=8
j = [2 + S[1] + K[1]] mod 4 = 5 mod 4 = 1
Swap(State[1], State[1]) = Swap(1,1)
State[0]=2 State[1]=1 State[2]=0 State[3]=3
Please do advise whether am i correct or wrong by mailing on the above email id.
And if wrong please advise why?

Awaiting Your Response.

2. samantha | 21 Nov 2008 12:56 PM

no one is explaining in appreciated way.When you explain something,it should be simple and using diagrams as well.
thank you
samantha

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